Sample post to see if this works.
Let’s try some Latex. \(e^{\pi i} + 1 = 0\).
\[\sum_{n=1}^{\infty} \frac{1}{n^2} = \frac{\pi^2}{6}\]Sample post to see if this works.
Let’s try some Latex. \(e^{\pi i} + 1 = 0\).
\[\sum_{n=1}^{\infty} \frac{1}{n^2} = \frac{\pi^2}{6}\]